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Question

Find the vector equation of the line joining points 2^i+^j+3^k and 4^i+3^j^k .

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Solution

Consider the given points be A and B

OA=2^i+^j+3^kOB=4^i+3^j^k

Therefore, coordinates of point A and B are (2,1,3) and (4,3,1) respectively.

Direction ratios of the line AB are proportional to (42),(31),(13)
i.e.
3,1,2

Thus vector equation of the line is

r=a+λb

r=(2^i+^j+3^k)+λ(3^i^j+2^k)

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