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Question

Find the vector equation of the plane passing through the intersection of the planes r(2i+2j3k)=7,r(2i+5j+3k)=9 and through the point (2,1,3)

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Solution

π1=r(2^i+2^j3^k)=72x+2y3z=7π2=r(2^i+5^j+3^k)=92x+5y+3z=9planethroughlineofintersectoionofπ1andπ2is:(2x+2y3z7)+λ(2x+5y+3z9)=0(2+2λ)x+y(2+5λ)+z(3+3λ)79λ=02(2+2λ)+2+5λ+3(3+3λ)79λ=010+9λ=0λ=109(2+209)x+y(2+509)+z(3+309)79×109=038x9+68y9+3z9=1738x+68y+3z=153

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