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Byju's Answer
Standard XII
Mathematics
Equation of a Plane Parallel to a Given Plane
Find the vect...
Question
Find the vector equation of the plane passing through the point A (4, - 2,3 ) and parallel to the plane x + 2 y - 5 z + 8 = 0
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Solution
A
(
4
,
−
2
,
3
)
p
a
r
a
l
l
e
l
t
o
p
l
a
n
e
x
+
2
y
−
5
z
+
8
=
0
Normal vector to plane is
(
1
,
2
,
−
5
)
(
1
,
2
,
−
5
)
(
x
−
4
,
y
+
2
,
z
−
3
)
=
0
(
x
−
4
)
+
2
(
y
+
2
)
−
5
(
z
−
3
)
=
0
x
−
4
+
2
y
+
4
−
5
z
+
3
=
0
x
+
2
y
−
5
z
=
−
3
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Similar questions
Q.
The equation of the line passing through the points
(
1
,
–
2
,
3
)
and parallel to the planes
x
−
y
+
2
z
−
5
=
0
and
3
x
+
y
+
z
−
6
=
0
is
Q.
Find the equation of the plane which contains the line of intersection of the planes x
+
2y
+
3
z
-
4
=
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x
+
y
-
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+
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=
0 and whose x-intercept is twice its z-intercept. Hence, write the equation of the plane passing through the point (2, 3,
-
1) and parallel to the plane obtained above.
Q.
Find the vector equation (in scalar product form) of the plane containing the line of intersection of the planes x − 3y + 2z − 5 = 0 and 2x − y + 3z − 1 = 0 and passing through (1, −2, 3).
Q.
Find the equation of the plane passing through the line of intersection of the planes 2x − y = 0 and 3z − y = 0 and perpendicular to the plane 4x + 5y − 3z = 8.
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An equation of the plane passing through the point
(1,-1,2)and parallel to the plane 3x + 4y - 5z = 0
is
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