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Question

Find the vector equation of the sphere concentric with the sphere |r+(^i2^j3^k)|=5 and its radius is two times of that sphere.

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Solution

Vector equation of sphere
|r+(^i2^j3^k)|=5
Centre of sphere
c=(^i+2^j+3^k)
and a=5
Double radius 2a=2×5=10
Hence required vector equation be
|r(c)|=a
|r(^i+2^j+3^k)|=10
|r+(^i2^j3^k)|=10.

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