Find the vector equation of the sphere concentric with the sphere |→r+(^i−2^j−3^k)|=5 and its radius is two times of that sphere.
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Solution
Vector equation of sphere |→r+(^i−2^j−3^k)|=5 Centre of sphere →c=(−^i+2^j+3^k) and a=5 Double radius 2a=2×5=10 Hence required vector equation be |→r−(→c)|=a |→r−(−^i+2^j+3^k)|=10 |→r+(^i−2^j−3^k)|=10.