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Question

Find the vector parallel to the vector ^i2^j and has magnitude 25 units.

A
2^i+4^j
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B
2^i4^j
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C
3^i4^j
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D
2^i3^j
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Solution

The correct option is B 2^i4^j
Let a=^i2^j
So, |a|=12+(2)2=5
Thus, the unit vector is given as
^a=a|a|
^a=^i2^j5

Let b be the vector parallel to a having magnitude 25 units
|b|=25
Now, b=|b|.^a (25).^i2^j5
b=2^i4^j

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