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Question

# Find the velocity of images formed due to a point object O w.r.t. ground if the mirror is at rest. All speeds given are w.r.t a stationary ground observer

A
25 m/s towards mirror
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B
45 m/s towards mirror
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C
25 m/s away from mirror
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D
45 m/s away from mirror
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Solution

## The correct option is B 45 m/s towards mirrorFor the velocity component along the principal axis, (VIM)=−v2u2(VOM) where VIM=Velocity of image w.r.t mirror. VOM=Velocity of object w.r.t mirror. Apply mirror equation: 1v+1u=1f⇒1v+1−20=1−30⇒v=+60 cm⇒m=−vu=−60−20=3 Since mirror is at rest (given that): (VIM)=−(3)2×(VOM)=−9×5=−45 m/s⇒→VIG=→VIM+→VMG =−45+0=−45 m/s That means images approaches the mirror with velocity 45 m/s.

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