Question

Find the vertex of the following quadratic equation and plot the graph:
$y=x^2-8x$.

Answer 1

$y=x^2-8x,a=1,b=-8,c=0$

Vertex, $x=-\frac{b}{2a}=-\left(\frac{-8}{2\times 1}\right)=4$

At $x=4,y=4^2-8\times 4=-16$

At $x=0,y=0$

At $x=8,y=0$