Question

Find the voltmeter and ammeter reading in the above circuit.

• A. 0V, 0A
• B. 5V, 0.5A
• C. 0V, 1 A
• D. 5V, 1 A

Answer 1

The correct option is C

0V, 1 A

The upper resistor is shorted with an ideal wire so all the current flows through it, instead of passing through the 10 $\Omega$ resistance.So, there will be no potential difference. Thus, effective resistance in the circuit is 10 $\Omega$​ only and potential in the circuit is 10 V.
From Ohm's law, V = IR
I = $\frac{V}{R}$ = $\frac{10}{10}$ = 1A