Find the voltmeter and ammeter reading in the above circuit.
0V , 1 A
The upper Resistor is shorted with an ideal wire so all the current flows through it instead of passing through the 10-ohm resistance.So no potential difference.
So effective resistance in the circuit is 10 ohm only and potential in the circuit is 10 v so total current is by ohm’s law.
V=IR. I= VR = 1010 = 1A