Find the volume density of elastic energy of fresh water at a depth of $1000 m$

2.5 k J m^{- 3}

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25 k J m^{- 3}

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0.25 k J m^{- 3}

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Solution

The correct option is B $25 k J m^{- 3}$
Work done is $W = 1 / 2 \times s t r e s s \times s t r a i n$
$W = P Δ V / 2$
$W / V = P Δ V / 2 V$
also, Bulk modulus $B = | - P V / Δ V |$
so, $W / V = P^{2} / 2 B$
$P = ρ g h = 1000 k g / m^{3} \times 10 m / s^{2} \times 1000 m$ and $B = 2 \times 10^{9}$
So $W / V = 25 k J m^{- 3}$

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Find the volume density of elastic energy of fresh water at a depth of 1000m

The correct option is B 25kJm−3Work done is W=1/2×stress×strainW=PΔV/2W/V=PΔV/2Valso, Bulk modulus B=|−PV/ΔV|so, W/V=P2/2BP=ρgh=1000kg/m3×10m/s2×1000m and B=2×109So W/V=25kJm−3

Find the volume density of elastic energy of fresh water at a depth of $1000 m$