Find the volume occupied by 30 g of neon gas at STP.
The explanation for the correct option
Option(D) 33.6 L
Molar mass of neon gas = 20 g/mol
1 mole i.e.,20 g of neon gas occupies 22.4 L
30 g of neon gas will occupy 22.420×30=33.6 L
Hence, Option(D) 33.6L is the volume occupied by 30 ~\text{g}30 g of neon gas at STP.