Question

Find the volume of a cube whose surface area is

$\left(i\right)$ $96c{m}^2$

Answer 1

Given: Surface area of a cube$=96c{m}^2$

We know that,

Surface area of a cube $=6\times (\text{Side}{)}^2$

$\Rightarrow 6\times (\text{Side}{)}^2=96c{m}^2$

$\Rightarrow (\text{Side}{)}^2=16$

$\Rightarrow \text{Side}=\sqrt{16}$

$=4cm$

$\therefore$ Volume of a cube $=(\text{side}{)}^3$

$=(4cm{)}^3$

$=64c{m}^3$

Hence, the surface area of cube is $64c{m}^3.$