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Question

# Find the volume of a cuboid whose (i) length = 12 cm, breadth = 8 cm, height = 6 cm (ii) length =1.2 m, breadth = 30 cm, height = 15 cm (iii) length = 15 cm, breadth = 2.5 dm, height = 8 cm.

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Solution

## $\text{(i)}\phantom{\rule{0ex}{0ex}}\text{In the given cuboid, we have:}\phantom{\rule{0ex}{0ex}}\text{length=12 cm, breadth=8 cm and height=6 cm}\phantom{\rule{0ex}{0ex}}\therefore \text{Volume of the cuboid = length×breadth×height}\phantom{\rule{0ex}{0ex}}\text{=12×8×6}\phantom{\rule{0ex}{0ex}}{\text{=576 cm}}^{3}\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}\text{(ii)}\phantom{\rule{0ex}{0ex}}\text{In the given cuboid, we have:}\phantom{\rule{0ex}{0ex}}\text{length=1.2 m}\phantom{\rule{0ex}{0ex}}\text{=1.2×100 cm}\left(1 m = 100 cm\right)\phantom{\rule{0ex}{0ex}}\text{=120 cm}\phantom{\rule{0ex}{0ex}}\text{breadth=30 cm}\phantom{\rule{0ex}{0ex}}\mathrm{h}\text{eight=15 cm}\phantom{\rule{0ex}{0ex}}\therefore \text{Volume of the cuboid = length×breadth×height}\phantom{\rule{0ex}{0ex}}\text{=120×30×15}\phantom{\rule{0ex}{0ex}}{\text{=54000 cm}}^{3}\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}\text{(iii)}\phantom{\rule{0ex}{0ex}}\text{In the given cuboid, we have:}\phantom{\rule{0ex}{0ex}}\text{length=1.5 dm}\phantom{\rule{0ex}{0ex}}\text{=1.5×10}\left(1 dm = 10 cm\right)\phantom{\rule{0ex}{0ex}}\text{= 15 cm}\phantom{\rule{0ex}{0ex}}\text{breadth=2.5 dm=2.5×10 cm=25 cm}\phantom{\rule{0ex}{0ex}}\mathrm{h}\text{eight=8 cm}\phantom{\rule{0ex}{0ex}}\therefore \text{Volume of cuboid = length×breadth×height}\phantom{\rule{0ex}{0ex}}\text{=15×25×8}\phantom{\rule{0ex}{0ex}}{\text{=3000 cm}}^{3}$

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