Question

Find the volume of a frustum cone, whose base and upper area of a circle is 36 and 100 $m{m}^2$. The height of the cone is 32.5 mm.

• A. 6,270 $m{m}^3$
• B. 6,170 $m{m}^3$
• C. 2,123.33 $m{m}^3$
• D. 6,470 $m{m}^3$

Answer 1

Answer: (C)

2,123.33 $m{m}^3$

Volume of a frustum cone = $\frac{1}{3}(A_1+A_2+\sqrt{A_1{A}_2})h$

= $\frac{1}{3}(36+100+\sqrt{36\times 100})\times 32.5$

= $\frac{1}{3}(136+\sqrt{3600})\times 32.5$

= $\frac{1}{3}(136+60)\times 32.5$

= $\frac{1}{3}\times 196\times 32.5$

= 2,123.33 $m{m}^3$