Question

Find the volume of a frustum cone, whose base and upper area of a circle is 6 and 6 $c{m}^2$. The height of the cone is 100 cm.

• A. 600 $c{m}^3$
• B. 2,800 $c{m}^3$
• C. 3,800 $c{m}^3$
• D. 4,800 $c{m}^3$

Answer 1

The correct option is A 600 $c{m}^3$

Volume of a frustum cone $=\frac{1}{3}(A_1+A_2+\sqrt{A_1{A}_2})h$

$=\frac{1}{3}(6+6+\sqrt{6\times 6})\times 100$

$=\frac{1}{3}(12+\sqrt{36})\times 100$

$=\frac{1}{3}(12+6)\times 100$

$=\frac{1}{3}\times 18\times 100$

$=\frac{1,800}{3}$

$=600c{m}^3$