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Frustum of a Cone

Find the volu...

Question

Find the volume of a frustum cone, whose base and upper area of a circle is $40 c m^{2}$ and $90 c m^{2}$ . (Insert answer in nearest integer).

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Solution

Volume of a frustum cone = $\frac{1}{3} (A_{1} + A_{2} + \sqrt{A_{1} A_{2}}) h$
= $\frac{1}{3} (40 + 90 + \sqrt{40 \times 90}) 10$
= $\frac{1}{3} (130 + 60) 10$
= $633.33 c m^{3}$

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