Find the volume of a solid in the form of a right circular cylinder with hemi-spherical ends whose total length is 2.7 m and the diameter of each hemi-spherical end is 0.7 m.

Open in App

Solution

Radius of hemispherical ends = radius of cylinder

Total length = 2.7 m.

Height of cylinder

Volume of two hemispheres

Volume of cylinders

Hence,

Volume of solid = 0.1797+0.77 = 0.95 m³

Suggest Corrections

Similar questions

Q. Find the volume of a solid in the form of a right circular cylinder with hemispherical ends whose length is

2.7 m

and the diameter of each hemispherical end is

0.7 m

Q. A solid in the form of a light circular cylindrical with a hemi-spherical one end and a cone at other end . Radius of common base is

3.53.5cm. find total surface area of the solid.

Q. A balloon is in the form of right circular cylinder of radius

1.5 m

length

4 m

and is surmounted by hemi spherical ends. If the radius is increased by

0.01 m

& the length by

0.05 m

, the percentage change in the volume of balloon is

a b c d %

, then the value of abcd must be ?

A right circular cylinder having diameter 12 cm and height 15 cm is full of ice-cream. The ice-cream is to be filled in identical cones of height 12 cm and diameter 6 cm having a hemi-spherical shape on the top. Find the number of cones required.

Q. If a hemi-spherical dome has an inner diameter of 28 m, then its volume (in

m^{3}

) is

Join BYJU'S Learning Program

Find the volume of a solid in the form of a right circular cylinder with hemi-spherical ends whose total length is 2.7 m and the diameter of each hemi-spherical end is 0.7 m.

Radius of hemispherical ends = radius of cylinder Total length = 2.7 m. Height of cylinder Volume of two hemispheres Volume of cylinders Hence, Volume of solid = 0.1797+0.77 = 0.95 m3

Radius of hemispherical ends = radius of cylinder

Total length = 2.7 m.

Height of cylinder

Volume of two hemispheres

Volume of cylinders

Hence,

Volume of solid = 0.1797+0.77 = 0.95 m³