Question

Find the volume of a solid in the form of a right circular cylinder with hemispherical ends whose length is $2.7m$ and the diameter of each hemispherical end is $0.7m$

Answer 1

Volume of solid$=\pi r^{2}h+2\times \frac{2}{3}\pi r^3$

$\Rightarrow \pi r^2[h+\frac{4}{3}r]=\frac{22}{7}\times {\left(\frac{0.7}{2}\right)}^2[(2.7-2\times \frac{0.7}{2})+\frac{4}{3}\times \frac{0.7}{2}]$

$=\frac{22}{7}\times \frac{0.7}{2}\times \frac{0.7}{2}\times 2.47=0.95m^3$