Find the volume of cuboid whose dimensions are $(x^{2} - 2), (2 x + 4)$ and $(x - 3) .$

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Solution

Here,
$l = (x^{2} - 2)$
$b = (2 x + 4)$
$h = (x - 3)$
Volume of cuboid = $l \times b \times h$
$= (x^{2} - 2) (2 x + 4) (x - 3)$
$= (2 x^{3} + 4 x^{2} - 4 x - 8) (x - 3)$
$= (2 x^{4} + 4 x^{3} - 4 x^{2} - 8 x - 6 x^{3} - 12 x^{2} + 12 x + 24)$
$= 2 x^{4} + (- 2 x^{3}) + (- 16 x^{2}) + 4 x + 24$
$= 2 x^{4} - 2 x^{3} - 16 x^{2} + 4 x + 24$

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