Find the volume of largest possible cone can be curved out from hemispere of radius 'r'.

\frac{1}{3} π r^{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{2}{3} π r^{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1}{2}

(volume)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{14}{3} π r^{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct options are
B $\frac{1}{3} π r^{3}$
C $\frac{1}{2}$ (volume)
R.E.F image
for longest cone $h = r$ & $r = R$
$\Rightarrow V = \frac{π}{3} r^{2} h = \frac{π}{3} r^{3}$
$\Rightarrow V = \frac{1}{2} (v o l . o f h e m i s p h e r e)$

Suggest Corrections

Similar questions

Q. The maximum volume of a cone that can be carved out of a solid hemisphere of radius r is

(a)

3 {πr}^{2}

(b)

\frac{{πr}^{3}}{3}

(c)

\frac{{πr}^{2}}{3}

(d)

3 {πr}^{3}

Q. STATEMENT - 1 : The volume of largest sphere that can be carved out from
cube of side a cm is

\frac{1}{6} π a^{3}

STATEMENT - 2 : Volume of sphere is

\frac{4}{3} π r^{3}

and for largest sphere to carved from cube radius of sphere

=

side of cube

Q. Find the volume of largest possible cone can be curved out from hemisphere of radius 'r'.

Question 1
If the radius of a sphere is 2r, then its volume will be:

A) $\frac{4}{3} π r^{3}$
B) $4 π r^{3}$
C) $\frac{8}{3} π r^{3}$
D) $\frac{32}{3} π r^{3}$

Q. If volume of the hemispherical pond

= 523.908 m^{3}

, maximum depth (radius)

= r m

Volume of a hemisphere

= \frac{2}{3} π r^{3}

Join BYJU'S Learning Program

Find the volume of largest possible cone can be curved out from hemispere of radius 'r'.

The correct options are B 13πr3 C 12(volume)R.E.F image for longest cone h=r & r=R⇒V=π3r2h=π3r3⇒V=12(vol.ofhemisphere)

The correct options are
B $\frac{1}{3} π r^{3}$
C $\frac{1}{2}$ (volume)
R.E.F image
for longest cone $h = r$ & $r = R$
$\Rightarrow V = \frac{π}{3} r^{2} h = \frac{π}{3} r^{3}$
$\Rightarrow V = \frac{1}{2} (v o l . o f h e m i s p h e r e)$