Question

Find the volume of the space garbage collected in a single day.

• A. $33.25\times {10}^{15}{\text{m}}^3$
• B. $33.25\times {10}^9{\text{m}}^3$
• C. $33.25\times {10}^8{\text{m}}^3$
• D. $3.325\times {10}^9{\text{cm}}^2$

Answer 1

The correct option is B $33.25\times {10}^9{\text{m}}^3$

We can find the volume by multiplying length, width, and height.

Volume is:
$=3.8\times {10}^7\times 2.5\times {10}^5\times 3.5\times {10}^3$
$=3.8\times 2.5\times 3.5\times {10}^{7+5+3}$
$=33.25\times {10}^{15}{\text{cm}}^3$

$\text{Conversion of}{\text{cm}}^3{\text{to m}}^3$:
$1{cm}^3={10}^{-6}{m}^3$

$\therefore 33.25\times {10}^{15}\times {10}^{-6}$
$=33.25\times {10}^{15-6}(\because a^m\times a^n=a^{m+n})$
$=33.25\times {10}^9$

Therefore, the volume of the garbage is
$33.25\times {10}^9{\text{m}}^3$.