Find the volume of water which can be filled in a bucket of height 8 cm and radii of ends of the bucket are 9 cm and 3 cm.

$321 π c m^{3}$

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$312 π c m^{3}$

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$108 π c m^{3}$

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$324 π c m^{3}$

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Solution

The correct option is B
$312 π c m^{3}$

A bucket can be considered as a frustum of a cone.

Now, volume of the water which can be filled in the bucket = Volume of the frustum
$= \frac{π}{3} (r_{1}^{2} + r_{1} r_{2} + r_{2}^{2}) h$
$= \frac{π}{3} (9^{2} + 9 \times 3 + 3^{2}) 8 c m^{3} = 312 π c m^{3}$

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Find the volume of water which can be filled in a bucket of height 8 cm and radii of ends of the bucket are 9 cm and 3 cm.

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Find the volume of water which can be filled in a bucket of height 8 cm and radii of ends of the bucket are 9 cm and 3 cm.

The correct option is B 312π cm3 A bucket can be considered as a frustum of a cone. Now, volume of the water which can be filled in the bucket = Volume of the frustum =π3(r21+r1r2+r22)h =π3(92+9×3+32)8 cm3=312π cm3