The correct option is B 8.4 V
N1V1+N2V2+...NnVn=NxVx
3×0.25+1×0.75=Nx×(250+750)
Nx=1.5 N
1.5 N H2O2=0.75 M H2O2
1 litre of the solution contains 25.5 g H2O2 (0.75×34).
According to the equation,
2H2O2⟶2H2O+O2
68 g H2O2 gives 22.4 litre O2.
25.5 g H2O2 gives 8.4 litres.
Therefore, the volume strength of 1.5 H2O2 is 8.4 V.