Find the wavelength of the first line of spectral series of He+ ion whose interval between extreme lines is 1λ1−1λ2=27419.25cm−1 (Take Rydberg's constant R=109677cm−1,1109677=9.11×10−6cm)
A
4685∘A
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
46.85∘A
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
7896∘A
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
78.96∘A
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A4685∘A Determination of the series: Extreme lines means first line and last line. First line corresponds to transition from n1+1 to n1 The last line corresponds to transition from infinity to n1 1λ1−1λ2=RZ2[1n21−1∞2]−RZ2[1n21−1(n1+1)2]=RZ2(n1+1)2 27419.25=109677×22(n1+1)2 (n1+1)=4 n1=3
Hence series corresponds to Paschen series of He+ ion.