wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the wavelength of the first line of spectral series of He+ ion whose interval between extreme lines is 1λ11λ2=27419.25 cm1
(Take Rydberg's constant R=109677 cm1,1109677=9.11×106 cm)

A
4685 A
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
46.85 A
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
7896 A
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
78.96 A
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 4685 A
Determination of the series:
Extreme lines means first line and last line.
First line corresponds to transition from n1+1 to n1
The last line corresponds to transition from infinity to n1
1λ11λ2=RZ2[1n2112]RZ2[1n211(n1+1)2]=RZ2(n1+1)2
27419.25=109677×22(n1+1)2
(n1+1)=4
n1=3

Hence series corresponds to Paschen series of He+ ion.

Determination of wavelength of the first line:

1λ=109677×22×[132142]
λ=46.8514×108 m=4685.14 A

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Bohr's Model of a Hydrogen Atom
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon