Find the work done by tension (in J) on 1kg block when 4kg block moves down by 20cm after the system is released. All surfaces are frictionsless
A
4J
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B
6J
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C
5J
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D
Zero
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Solution
The correct option is C5J By the FBD of both the blocks, given that the block 4kg moves down by 0.2m so the block 1kg will move up the incline plane by 0.4m The acceleration of the block 4kg will be a downward and the acceleration of block 1kg will be 2a up the incline plane
∴ From both FBD, we get
40−2T=4a..(i)
T−1×10×sin30∘=1.(2a)..(ii)
From (i) & (ii), we get T=12.5N
∴ Work done due to tension =T×0.4 on 1kg block =12.5×0.4 WT=5J