Find the work done by the force in the given figure?

25 J

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22.5 J

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20 J

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17.5 J

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Solution

The correct option is D $17.5 J$
Work done = Area under F-x graph
= Area $△ O A P$ +Area of rectangle ABQP + area of rectangle CDRQ + Area of rectangle RSEF + Area of $△$ GTS
$W = \frac{1}{2} \times (1 - 0) \times 10 + (2 - 1) \times 10 + (3 - 2) \times 5 + (4 - 3) \times (- 5) + \frac{1}{2} \times (5 - 4) \times 5 W = 5 + 10 + 5 - 5 + 2.5 = 17.5 J$

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Find the work done by the force in the given figure?

The correct option is D 17.5 JWork done = Area under F-x graph = Area △OAP +Area of rectangle ABQP + area of rectangle CDRQ + Area of rectangle RSEF + Area of △ GTS W=12×(1−0)×10+(2−1)×10+(3−2)×5+(4−3)×(−5)+12×(5−4)×5W=5+10+5−5+2.5=17.5 J