The correct option is D −2πrμkN
The kinetic frictional force at any instantaneous position is Fk=μkN
→Fk acts tangentially opposite to the motion of the pencil.
For an infinitesimal displacement →dl, the work done by pencil is,
dW=−→Fk.→dl
⇒dW=−Fk(dl)
Now, the work done by the frictional force in drawing a circle of radius r,
⇒W=−∫2πr0Fkdl
⇒W=−μkN∫2πr0dl
⇒W=−μkN[2πr−0]
∴W=−2πμkNr
Hence, option (d) is the correct answer.