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Question

Find the work done (in kJ) when one mole of the gas is expanded reversibly and isothermally from 5atm to 1 atm at 25oC

A
10 kJ
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B
2 kJ
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C
8 kJ
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D
4 kJ
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Solution

The correct option is D 4 kJ
Work done in case of reversible isothermal process is given by

w=2.303nRT logP1P2
Given : P1=5 atm
P2=1 atm
n=1
T=25+273=298 K

w=2.303×1×8.314 ×298 log51
using log 5=0.693
w=3.98 kJ or 4 kJ

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