Find the work done in lifting a $50 k g$ bucket of water through a vertical height of $2 m$ .
(Take g= $10 m s^{- 2}$ )

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Solution

Step 1: Given data
Mass (m) = $50 k g$
Height (h) = $2 m$
Acceleration due to gravity (g) = $10 m s^{- 2}$
Step 2: Formula used
Work done, $W = F s \cos θ$ where F = Force, s = displacement, $θ$ = angle between the force and displacement.
Force, $F = m g$ where m = mass, g = acceleration due to gravity
Step 3: Finding force
$F = 50 k g x 10 m s^{- 2} F = 500 N$
Step 4: Finding work done
Here weight and displacement are along opposite directions.
$W = 500 x 2 x \cos 180 ° W = 1000 x - 1 W = - 1000 J$
Hence the magnitude of work done in lifting the bucket of water through a vertical height of $2 m$ is $1000 J$ .

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Find the work done in lifting a 50kg bucket of water through a vertical height of 2m.(Take g= 10ms-2)

Find the work done in lifting a $50 k g$ bucket of water through a vertical height of $2 m$ .
(Take g= $10 m s^{- 2}$ )