Question

Find the work done in placing a charge $8\times {10}^{-18}C$ on a condenser of capacity $100\mu F$.

Answer 1

Work done,$W=\frac{Q^2}{2C}=\left(\frac{1}{2}\right)\times \frac{(8\times {10}^{-18}{)}^2}{100\times \left({10}^{-6}\right)}=32\times {10}^{-32}J$