Find the work done to take a particle of mass $m$ from surface of the earth to a height equal to $2 R$ -

2 mg R

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\frac{mg R}{2}

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3 mgR

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\frac{2 mg R}{3}

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Solution

The correct option is D $\frac{2 mg R}{3}$
work done by conservative force $= - Δ U$
$W = GM m [\frac{1}{R} - \frac{1}{3 R}]$
$= \frac{2 GM m}{3 R} = \frac{2}{3} mg R$

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Find the work done to take a particle of mass m from surface of the earth to a height equal to 2R -

The correct option is D 2mg R3work done by conservative force =−ΔU W=GM m[1R−13R] =2GM m3R=23mg R

Find the work done to take a particle of mass $m$ from surface of the earth to a height equal to $2 R$ -

The correct option is D $\frac{2 mg R}{3}$
work done by conservative force $= - Δ U$
$W = GM m [\frac{1}{R} - \frac{1}{3 R}]$
$= \frac{2 GM m}{3 R} = \frac{2}{3} mg R$