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Question

Find the work done when 2 moles of hydrogen expands isothermally from 15 L to 50 L against a constant pressure of 1 atm at 250C.

A
820.8 cal
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B
848.2 cal
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C
84.7 cal
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D
848.2 kcal
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Solution

The correct option is B 848.2 cal
We know, work done for an isothermal process is given as:
W=Pext(V2V1)
where Pext= external pressure = 1 atm
V2= final volume = 50 L
V1 = initial volume = 15 L
W=1×35=35 L atm
and 1 L atm=101.3 J
So, W=35×101.3 J=3545.5 J
We know 1 cal=4.18 J
W=3545.54.18 cal
so, W=848.2 cal

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