find the work done when a body of mass 500 g moving with a velocity of 20m/s suddenly stops when brakes are applied

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Solution

Dear Student,

$W o r k D o n e = - (C h a n g e i n K i n e t i c e n e r g y) 500 g = \frac{500}{1000} k g = 0.5 k g k i n e t i c e n e r g y = \frac{1}{2} m v^{2} C h a n g e i n k i n e t i c e n e r g y = F i n a l k i n e t i c e n e r g y - i n i t i a l k i n e t i c e n e r g y = \frac{1}{2} (0.5) \times {(0)}^{2} - \frac{1}{2} (0.5) \times {(20)}^{2} = - \frac{1}{2} (0.5) (400) = - 100 J W o r k d o n e = - (- 100) = 100 J$

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find the work done when a body of mass 500 g moving with a velocity of 20m/s suddenly stops when brakes are applied

Dear Student, Work Done=-(Change in Kinetic energy)500 g=5001000kg=0.5 kgkinetic energy=12mv2Change in kinetic energy=Final kinetic energy-initial kinetic energy =12(0.5)×02-12(0.5)×(20)2=-12(0.5)(400) =-100 JWork done=-(-100)=100J Regards,