7
You visited us
7
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XII
Chemistry
Thermodynamic Processes
Find the work...
Question
Find the work done when one mole of the gas is expanded reversibly and isothermally from 5 atm to 1 atm at
25
0
C
.
Open in App
Solution
In isothermal process
W
=
n
R
T
ln
(
P
2
P
1
)
=
n
R
T
ln
(
V
1
V
2
)
∴
W
=
1
×
R
×
298
×
ln
(
5
1
)
=
298
×
R
×
ln
5
=
9.298
×
25
3
×
ln
5
J
=
3996.77
J
Suggest Corrections
0
Similar questions
Q.
The work done when one mole of the gas is expanded reversibly and isothermally from 1 atm to 5 atm at
25
o
C
is:
Q.
Find the work done when
1
mole of the gas is expanded reversibly and isothermally from
5
a
t
m
to
1
a
t
m
at
25
o
C
.
Q.
Find the work done (in
k
J
) when one mole of the gas is expanded reversibly and isothermally from
5
a
t
m
to
1
a
t
m
at
25
o
C
.
Q.
Find the work done (in
k
J
) when one mole of the gas is expanded reversibly and isothermally from
5
a
t
m
to
1
a
t
m
at
25
o
C
.
Q.
Calculate the work done in joules when
3
moles of an ideal gas at
27
o
C
expands isothermally and reversibly from
10
atm to
1
atm.
(
1
a
t
m
=
1.013
×
10
5
N
m
−
2
)
.
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
First Law of Thermodynamics
CHEMISTRY
Watch in App
Explore more
Thermodynamic Processes
Standard XII Chemistry
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app