Find the wrong term of the series :
$3, 6, 24, 30, 63, 72, 122, 132$

132

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30

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122

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72

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Solution

The correct option is D $122$
The given series: 3, 6, 24, 30, 63, 72, 122, 132 consists of two series.
Here each of the given term has 3 as the common factor except 122, which is the wrong term.
Hence, option (C) is the correct answer.

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