Question

Find the $xandy$ in the following figure:

Answer 1

From the $\Delta PSR$ we have $\angle PSR={90}^o$, $\angle SPR={40}^o$ then $y={180}^o-({90}^o+{40}^o)={50}^o$.

Similarly from $\Delta PQS$ we've, $\angle PSQ={90}^o$, $\angle PQS={60}^o$.

Then $x=\angle QPS={180}^o-({90}^o+{60}^o)={30}^o$.