Question

Find the $X$ and $Y$ intercept of the line $x-3y-4=0$

Answer 1

$x-3y-4=0$

$\Rightarrow x-3y=4$

Divide both sides by $4$ we get

$\Rightarrow \frac{x}{4}+\frac{3y}{-4}=1$

$\Rightarrow \frac{x}{4}+\frac{y}{\frac{-4}{3}}=1$

$\therefore x-$ intercept is $=4$ and $y-$intercept is $\frac{-4}{3}$