Find the $x$ intercept of the graph $y = x^{2} + 2 x - 5$ .

-1

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1 - \sqrt{6}

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1 + \sqrt{6}

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- 1 - \sqrt{6}

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Solution

The correct option is D $- 1 - \sqrt{6}$
To find the $x$ - intercept, we need to equate y to $0$ .
Doing that, we get $0 = x^{2} + 2 x - 5$
$\Rightarrow x = \frac{- 2 \pm \sqrt{4 + 20}}{2}$
$\Rightarrow x = \frac{- 2 \pm 2 \sqrt{6}}{2}$
$\Rightarrow x = - 1 - \sqrt{6}, - 1 + \sqrt{6}$

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