Find the $x, y$ intercepts of the straight line $4 y = - x + 3$ .

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Solution

Given the equation of the line is
$4 y = - x + 3$
or, $x + 4 y = 3$
or, $\frac{x}{3} + \frac{y}{\frac{3}{4}} = 1$ .
So the $x, y$ intercepts are respectively $3, \frac{3}{4}$ .

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