Question

Find the zero of the polynomial in each of the following cases:
(i) p(x) = 3x - 2
(ii) p(x) = 3x
(iii) p(x) = ax, a $\ne$ 0
(iv) p(x) = cx + d, c $\ne$ 0, c, d are real numbers.

Answer 1

(i) $3x-2=0\Rightarrow 3x=2\Rightarrow x=\frac{2}{3},so\frac{2}{3}$ is the zero of 3x - 2.

(ii) $3x=0,\Rightarrow x=0,$ so 0 is the zero of 3x.

(iii) $ax=0(a\ne 0)\Rightarrow x=\frac{0}{a}=0,$ so, is the zero of ax.

(iv) $cx+d=0(c\ne 0)\Rightarrow cx=-d\Rightarrow x=\frac{-d}{c},so,\frac{-d}{c}$ is the 0 of cx + d.