Question

Find the zero of the polynomial $p\left(x\right)=cx+d,c\ne 0$, \ c, d are real numbers.

• A. $\frac{c}{d}$
• B. $-\frac{c}{d}$
• C. $\frac{d}{c}$
• D. $-\frac{d}{c}$

Answer 1

Answer: (D)

$-\frac{d}{c}$

Here, $p\left(x\right)=cx+d,c\ne 0$.
In order to find zero of $p\left(x\right)$, we equate $p\left(x\right)$ to 0,
$i.e$ $p\left(x\right)=0$.
$\Rightarrow cx+d=0\Rightarrow cx=-d\Rightarrow x=\frac{-d}{c}$ .
$\therefore \frac{-d}{c}$ is the zero of $p\left(x\right)$.
Therefore, option $D$ is correct.