Question

Find the zero of the polynomials in the following case: $p\left(x\right)=cx+d,c\ne 0,c,d$ are real numbers.

Answer 1

The given polynomial is $p\left(x\right)=cx+d,c\ne 0$.

We know that the zeroes of a polynomial are evaluated by equating them with zero.

$\therefore p\left(x\right)=0$

$\Rightarrow cx+d=0$

$\Rightarrow$ $cx=-d$

$\Rightarrow$ $x=-\frac{d}{c}$

Hence, the zero of this polynomial is $-\frac{d}{c}$.