Find the zeroes of f(x) = 18x - 72.

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Solution

The correct option is B 4
To find zeroes of the polynomial f(x), We equate f(x)=0.
$⟹ 18 x - 72 = 0$
$⟹ x = \frac{72}{18}$
$⟹ x = 4$
Hence, 4 is the zero of the linear polynomial, f(x) = 18x - 72.

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