Find the zeroes of polynomial $p (x) = 6 x^{2} - 3$

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Solution

We have,

$P (x) = 6 x^{2} - 3$

Zeros of polynomial is

$p (x) = 0$

$6 x^{2} - 3 = 0$

$6 x^{2} = 3$

$x^{2} = \frac{3}{6}$

$x^{2} = \frac{1}{2}$

$x = \pm \sqrt{\frac{1}{2}}$
Hence, this is the answer.

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