Question

Find the zeroes of polynomial $p\left(x\right)=6x^2-3$

Answer 1

We have,

$P\left(x\right)=6x^2-3$

Zeros of polynomial is

$p\left(x\right)=0$

$6x^2-3=0$

$6x^2=3$

$x^2=\frac{3}{6}$

$x^2=\frac{1}{2}$

$x=\pm \sqrt{\frac{1}{2}}$

Hence, this is the answer.