Question

Find the zeroes of the following polynomial by factorization method: $3x^2+4x-4$.

Answer 1

Factorise the given polynomial to find its zeroes

Given, $3x^2+4x-4$

First, we will split the middle term.

$3x^2+4x-4=3x^2+6x-2x-4$

$=3x(x+2)-2(x+2)$ [ taking the common terms out ]

$=(x+2)(3x-2)$

We can find the zeroes as

$(x+2)(3x-2)=0$

$(x+2)=0$ or $(3x-2)=0$

$x=-2$ or $x=\frac{2}{3}$

Hence, the zeroes of the polynomial are $-2$ and $\frac{2}{3}$.