Find the zeroes of the following polynomial:
$p (x) = (x - 1) (x - 2) (x - 3)$ .

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Solution

The correct options are
A 1
B 2
C 3
Finding zero of $p (x) = (x - 1) (x - 2) (x - 3)$ , is same as solving the equation $p (x) = 0$ .

$\Rightarrow (x - 1) (x - 2) (x - 3) = 0$

$\Rightarrow (x - 1) = 0, (x - 2) = 0, (x - 3) = 0$
$\Rightarrow x = 1, 2, 3$ .

Therefore, options $A$ , $B$ and $C$ are correct.

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Similar questions

Give zeroes of the polynomial p(x)=(x-1)(x-2)(x-3)(x-4)

Verify whether the following are zeroes of the polynomial, indicated against them.

(i) (ii)

(iii) p(x) = x² − 1, x = 1, − 1 (iv) p(x) = (x + 1) (x − 2), x = − 1, 2

(v) p(x) = x², x = 0 (vi) p(x) = lx + m

(vii) (viii)

p (x) = (x + 1) (x - 2), x = - 1, 2

p (x) = (x + 2) (x + 3)

- \frac{1}{2}

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