Find the zeroes of the following quadratic polynomial.
$5 x^{2} + 8 x + 3$
$- 21 x^{2} + 16 x + 5$

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Solution

$1$
$5 x^{2} + 8 x + 3 = 0$
$5 x^{2} + 5 x + 3 x + 3 = 0$
$5 x (x + 1) + 3 (x + 1) = 0$
$(5 x + 3) (x + 1) = 0$

$2$
$- 21 x^{2} + 16 x + 5 = 0$
$21 x^{2} - 16 x - 5 = 0$
$21 x^{2} - 21 x + 5 x - 5 = 0$
$21 x (x - 1) + 5 (x - 1)$
$(x - 1) (21 x + 5)$

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Find the zeroes of the following quadratic polynomial.5x2+8x+3−21x2+16x+5

15x2+8x+3=05x2+5x+3x+3=05x(x+1)+3(x+1)=0(5x+3)(x+1)=02−21x2+16x+5=021x2−16x−5=021x2−21x+5x−5=021x(x−1)+5(x−1)(x−1)(21x+5)

Find the zeroes of the following quadratic polynomial.
$5 x^{2} + 8 x + 3$
$- 21 x^{2} + 16 x + 5$

$1$
$5 x^{2} + 8 x + 3 = 0$
$5 x^{2} + 5 x + 3 x + 3 = 0$
$5 x (x + 1) + 3 (x + 1) = 0$
$(5 x + 3) (x + 1) = 0$

$2$
$- 21 x^{2} + 16 x + 5 = 0$
$21 x^{2} - 16 x - 5 = 0$
$21 x^{2} - 21 x + 5 x - 5 = 0$
$21 x (x - 1) + 5 (x - 1)$
$(x - 1) (21 x + 5)$