The correct option is C 56,−1
6x2+x−5=0
We need to find two numbers 'a' and 'b' such that
a±b=1,a×b=−30
⇒6−5=1,−5×6=−30
6x2+6x−5x−5=0
6x(x+1)−5(x+1)=0
(6x−5)(x+1)=0
So,
6x−5=0
⇒x=56
or,
x+1=0
⇒x=−1
Thus, the zeroes of the polynomial
6x2+x−5 are 56 and -1.