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Question

Find the zeroes of the following quadratic polynomial:
6x2+x5

A
12,1
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B
6, 5
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C
56,1
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D
2, 1
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Solution

The correct option is C 56,1
6x2+x5=0
We need to find two numbers 'a' and 'b' such that
a±b=1,a×b=30
65=1,5×6=30
6x2+6x5x5=0
6x(x+1)5(x+1)=0
(6x5)(x+1)=0
So,
6x5=0
x=56

or,
x+1=0
x=1
Thus, the zeroes of the polynomial
6x2+x5 are 56 and -1.

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